Difference between revisions of "Talk:Automatically trimming a monodix"

From Apertium
Jump to navigation Jump to search
 
(9 intermediate revisions by 2 users not shown)
Line 1: Line 1:
  +
== HFST: possible to overcome compound overgeneration? ==
==Implementing automatic trimming in lttoolbox==
 
The current method: compile the analyser in the normal way, then lt-trim loads it and loops through all its states, trying to do the same steps in parallel with the compiled bidix:
 
   
  +
Assuming we ''don't use flags'', we can compile an HFST transducer through [[ATT]] format to a working lttoolbox transducer.
<pre>
 
trim(current_a, current_b):
 
   
  +
Now the issue is that compounds are plain transitions back into some lexicon, without the compound-only-L/compound-R tags, so even though lt-trim should trim the compounds correctly (by treating them like &lt;j/&gt; transitions), the resulting analyser will over-generate:
for symbol, next_a in analyser.transitions[current_a]:
 
   
  +
<pre>jīvitarēkha/jīvitarēkha<n><sg><nom>/jīvitaṁ<n><cmp>+rēkha<n><sg><nom></pre>
found = false
 
   
  +
Ie. we will get non-lexicalised compound analyses along with the lexicalised ones.
for s, next_b in bidix.transitions[current_b]:
 
if s==symbol:
 
trim(next_a, next_b)
 
found = true
 
if seen tags:
 
found = true
 
   
  +
One way to overcome this is to first compile the analyser from the ATT, then:
if !found && !current_b.isFinal():
 
  +
* go through it building a new version, but on seeing a +, we:
delete symbol from analyser.transitions[current_a]
 
  +
** replace the transition with a single compound-only-L tag transitioning into final state
  +
** let partial=copy_until_final(the_plus_transition) and make a transition from start into partial, and we connect the final state of partial with a single tag compound-R into the final state of our new FST
   
  +
If the function copy_until_final sees a +, that transition is discarded, but a compound-only-L tag is added.
// else: all transitions from this point on will just be carried over unchanged by bidix
 
   
trim(analyser.initial, bidix.initial)
 
</pre>
 
   
  +
Note: this compounding method won't let you do stuff like "only allow adj adj or noun noun compounds" like you can in HFST.
[[Image:Product-automaton-intersection.png|thumb|400px|right|product automaton for intersection]]
 
   
  +
::You can do that in the morphotactics though (e.g. adjective paradigms only redirect to the adjectivestem lexicon.) - [[User:Francis Tyers|Francis Tyers]] ([[User talk:Francis Tyers|talk]]) 13:33, 22 May 2014 (CEST)
Trimming while reading the XML file might have lower memory usage, but seems like more work, since pardefs are read before we get to an "initial" state.
 
   
  +
: Uh, what happens if you simply specify compound-R and compound-only-L tags in the lexc?
A slightly different approach is to create the '''product automaton''' for intersection, marking as final only state-pairs where both parts of the state-pair are final in the original automata. Minimisation should remove unreachable state-pairs. However, this quickly blows up in memory usage since it creates ''all'' possible state pairs first (cartesian product), not just the useful ones.
 
   
  +
::This is also an option, while we were at it I'd choose a prettier couple of symbols though ;) - [[User:Francis Tyers|Francis Tyers]] ([[User talk:Francis Tyers|talk]]) 13:33, 22 May 2014 (CEST)
https://github.com/unhammer/lttoolbox/branches has some experiments, see e.g. branches product-intersection and df-intersection
 
   
<br clear="all" />
 
   
  +
Say we have the FST "bidix", can we create "<code>bidix [^+]* (+ bidix [^+]*)*</code>" (where + is just the literal join symbol) and trim with that?
===TODO===
 
  +
: seems to work!
* Would it make things faster if we first clear out the right-sides of the bidix and minimize that?
 
* remove all those ifdef DEBUG's and wcerr's
 
* more tests?
 
* if no objections: git svn dcommit
 
 
== + type multiwords ==
 
join (&lt;j&gt;) is handled by setting the next trimmer (bidix) target state to be trimmer.initial, so we simply skip to the start.
 
=== + and # together ===
 
''However'', if we have a + followed by a # in monodix, we need to get back to where we were after reading the + part. An example:
 
<pre>monodix, one entry:
 
foo<n><ind>+bar<pr># fie
 
 
bidix, two entries:
 
foo# fie<n>
 
bar<pr>
 
 
preprocessed (prefixed+lemq-moved) bidix, two entries:
 
foo<n>[<n>|<ind>|<pr>]*# fie
 
bar<pr>[<n>|<ind>|<pr>]*
 
</pre>
 
 
We start by matching on these paths: <pre>
 
monodix string foo<n><ind> + bar<pr> # fie
 
monodix states g i j k
 
bidix string foo<n>[<n>|<ind>|<pr>]* # fie
 
bidix states l m
 
</pre>
 
and get as far as state pair (i,m), having consumed <pre>foo<n><ind></pre> before seeing a +.
 
 
Now, the next SearchState records both the next monodix state (j, the state after +), the next bidix state (l, the bidix initial state), and the bidix state we were in when we saw the plus (m, at the end of the bidix tag list). So in the code SearchState next = (this_trg, trimmer.initial, trimmer_src).
 
 
At (i,l,m) we've consumed <pre>foo<n><ind></pre> and have <pre>bar<pr># fie</pre> left, and can read from bidix initial l:<pre>
 
monodix string bar<pr> # fie
 
monodix states j k
 
bidix string bar<n>[<n>|<ind>|<pr>]*
 
bidix states l n
 
</pre>
 
 
We match all of <pre>bar<pr></pre> and then see a # in monodix, giving SearchState (k,n,m). Since both the third part of SearchState is set to state m (where m!=n), and we've seen a #, we jump back to that state m, from where we can match <code># fie</code>, and we're done.
 
 
== Compounds vs trimming in HFST ==
 
 
The sme.lexc can't be trimmed using the simple HFST trick, due to compounds.
 
 
Say you have '''cake n sg''', '''cake n pl''', '''beer n pl''' and '''beer n sg''' in monodix, while bidix has '''beer n''' and '''wine n'''. The HFST method without compounding is to intersect '''(cake|beer) n (sg|pl)''' with '''(beer|wine) n .*''' to get '''beer n (sg|pl)'''.
 
 
But HFST represents compounding as a transition from the end of the singular noun to the beginning of the (noun) transducer, so a compounding HFST actually looks like
 
: '''((cake|beer) n sg)*(cake|beer) n (sg|pl)'''
 
The intersection of this with
 
: '''(beer|wine) n .*'''
 
is
 
: '''(beer n sg)*(cake|beer) n (sg|pl) | beer n pl'''
 
when it should have been
 
: '''(beer n sg)*(beer n (sg|pl)'''
 
 
 
Lttoolbox doesn't represent compounding by extra circular transitions, but instead by a special restart symbol interpreted while analysing.
 
lt-trim is able to understand compounds by simply skipping the compund tags
 

Latest revision as of 14:47, 20 June 2014

HFST: possible to overcome compound overgeneration?[edit]

Assuming we don't use flags, we can compile an HFST transducer through ATT format to a working lttoolbox transducer.

Now the issue is that compounds are plain transitions back into some lexicon, without the compound-only-L/compound-R tags, so even though lt-trim should trim the compounds correctly (by treating them like <j/> transitions), the resulting analyser will over-generate:

jīvitarēkha/jīvitarēkha<n><sg><nom>/jīvitaṁ<n><cmp>+rēkha<n><sg><nom>

Ie. we will get non-lexicalised compound analyses along with the lexicalised ones.

One way to overcome this is to first compile the analyser from the ATT, then:

  • go through it building a new version, but on seeing a +, we:
    • replace the transition with a single compound-only-L tag transitioning into final state
    • let partial=copy_until_final(the_plus_transition) and make a transition from start into partial, and we connect the final state of partial with a single tag compound-R into the final state of our new FST

If the function copy_until_final sees a +, that transition is discarded, but a compound-only-L tag is added.


Note: this compounding method won't let you do stuff like "only allow adj adj or noun noun compounds" like you can in HFST.

You can do that in the morphotactics though (e.g. adjective paradigms only redirect to the adjectivestem lexicon.) - Francis Tyers (talk) 13:33, 22 May 2014 (CEST)
Uh, what happens if you simply specify compound-R and compound-only-L tags in the lexc?
This is also an option, while we were at it I'd choose a prettier couple of symbols though ;) - Francis Tyers (talk) 13:33, 22 May 2014 (CEST)


Say we have the FST "bidix", can we create "bidix [^+]* (+ bidix [^+]*)*" (where + is just the literal join symbol) and trim with that?

seems to work!