Talk:Automatically trimming a monodix

Implementing automatic trimming in lttoolbox

The current method: compile the analyser in the normal way, then lt-trim loads it and loops through all its states, trying to do the same steps in parallel with the compiled bidix:

trim(current_a, current_b):

  for symbol, next_a in analyser.transitions[current_a]:

    found = false

    for s, next_b in bidix.transitions[current_b]:
      if s==symbol:
         trim(next_a, next_b)
         found = true
    if seen tags: 
      found = true

    if !found && !current_b.isFinal():
      delete symbol from analyser.transitions[current_a]

    // else: all transitions from this point on will just be carried over unchanged by bidix

trim(analyser.initial, bidix.initial)

product automaton for intersection

Trimming while reading the XML file might have lower memory usage, but seems like more work, since pardefs are read before we get to an "initial" state.

A slightly different approach is to create the product automaton for intersection, marking as final only state-pairs where both parts of the state-pair are final in the original automata. Minimisation should remove unreachable state-pairs. However, this quickly blows up in memory usage since it creates all possible state pairs first (cartesian product), not just the useful ones.

https://github.com/unhammer/lttoolbox/branches has some experiments, see e.g. branches product-intersection and df-intersection

#-type multiwords

The implementation: first "preprocess" (in memory) the bidix FST so it has the same format as the analyser, ie. instead of "take# out<vblex>" it has "take<vblex># out".

Say you have these entries in the bidix:

take# out<vblex>
take# out<n>
take# in<vblex>
take<n>
take<vblex>

We do a depth-first traversal, and then after reading all of "take", we see t=transition(A, B, ε, #). We remove that transition, and instead add the result of copyWithTagsFirst(t), which returns a new transducer that represents these partial analyses:

<vblex># out
<n># out
<vblex># in

pseudocode

def moveLemqsLast()
  new_t = Transducer()
  seen = set()
  todo = [initial]
  while todo:
    src = todo.pop()
    for left, right, trg in transitions[src]:
      if left == '#':
        new_t.transitions[src][epsilon].insertTransducer( copyWithTagsFirst(trg) )
      else:
        new_t.linkStates(src, trg, left, right)
        if trg not in seen:
          todo.push(trg)
    seen.insert(trg)
  return new_t

def copyWithTagsFirst(start):
  seen = set()
  new_t = Transducer()
  lemq = Transducer()
  m = { start: new_t.initial }
  finally = []
  todo = [(start,start)]
  while todo:
    src,lemq_last = todo.pop()
    for left, right, trg in transitions[src]:
      if not isTag(left):
        lemq.linkStates(src, trg, label)
        if trg,trg not in seen:
          todo.push((trg, trg))
      else:
        if src == lemq_last
          new_t.linkState(m[start], m[trg], epsilon)
        else:
          new_t.linkState(m[src], m[trg], label)
        if src in finals:
          finally.insert((src, lemq_last))
        if src,lemq_last not in seen:
          todo.push((trg, lemq_last)) 
    seen.insert((src, lemq_last))
  for lasttag, lemq_last in finally:
    newlemq = Transducer(lemq) # copy lemq
    newlemq.finals = set(lemq_last) # let lemq_last be the only final state in newlemq
    newlemq.minimize()
    new_t.insertTransducer(m[lasttag], newlemq) # append newlemq after finaltag
  return new_t

Compounds vs trimming in sme

The sme.lexc can't be trimmed using the simple HFST trick, due to compounds.

Say you have cake n sg, cake n pl, beer n pl and beer n sg in monodix, while bidix has beer n and wine n. The HFST method without compounding is to intersect (cake|beer) n (sg|pl) with (beer|wine) n .* to get beer n (sg|pl).

But HFST represents compounding as a transition from the end of the singular noun to the beginning of the (noun) transducer, so a compounding HFST actually looks like

((cake|beer) n sg)*(cake|beer) n (sg|pl)

The intersection of this with

(beer|wine) n .*

is

(beer n sg)*(cake|beer) n (sg|pl) | beer n pl

when it should have been

(beer n sg)*(beer n (sg|pl)

Lttoolbox doesn't represent compounding by extra circular transitions, but instead by a special restart symbol interpreted while analysing. When we have lt-trim we will be able to make it understand compounds by e.g. restarting on +