Difference between revisions of "Format dictionaries"

From Apertium
Jump to navigation Jump to search
m
 
(14 intermediate revisions by 7 users not shown)
Line 1: Line 1:
{{Otherlang|Formatage de dictionnaires|{{French}}}}
You can use the dictools script ([[Crossdics|crossdics]] package) to format each '''<code><e></code>''' tag in the dictionary.


You can use the [[Apertium-dixtools]] package to format each '''<code><e></code>''' tag in the dictionary.
$ ./dictools format-1line <dic> <dic.out>


$ apertium-dixtools '''format-1line''' <dic> <dic.out>

(''Note that the first character in the '''1line''' parameter is the digit '''1''' (one), not the lowercase "L".'')


For example, these lines:
For example, these lines:
Line 17: Line 20:
</pre>
</pre>


will be displayed in one line.
will be displayed in one line, instead of being indented to various levels on six lines:


<pre>
<pre>
Line 25: Line 28:
</pre>
</pre>


This single-line format can be useful if you use [http://es.wikipedia.org/wiki/Grep grep] or any similar tool to process dictionaries.
[[Category:Documentation]]

== Aligned formatting ==
You can also add two parameters, namely the positon of the &lt;p&gt; element and the position of the &lt;r&gt; element.
Here alignP = 10 and alignR = 50:
<pre>
<!-- Conjunctions - Conjunctive adverb -->

<e> <p><l>antaŭ<b/>ol<s n="cnjadv"/></l> <r>before<s n="cnjadv"/></r></p></e>
<e> <p><l>tiel<b/>ke<s n="cnjadv"/></l> <r>so<b/>that<s n="cnjadv"/></r></p></e>
<e> <p><l>krom<b/>se<s n="cnjadv"/></l> <r>unless<s n="cnjadv"/></r></p></e>
<e> <p><l>dum<s n="cnjadv"/></l> <r>whereas<s n="cnjadv"/></r></p></e>
<e> <p><l>ĉar<s n="cnjadv"/></l> <r>because<s n="cnjadv"/></r></p></e>
<e r="RL"><p><l>dum<s n="cnjadv"/></l> <r>while<s n="cnjadv"/></r></p></e>
<e> <p><l>ĝis<s n="cnjadv"/></l> <r>until<s n="cnjadv"/></r></p></e>
<e> <p><l>kiam<s n="cnjadv"/></l> <r>when<s n="cnjadv"/></r></p></e>
<e i="yes"><p><l>kiam<s n="cnjadv"/></l> <r>as<s n="cnjadv"/></r></p></e>
<e> <p><l>kiel<s n="cnjadv"/></l> <r>as<s n="cnjadv"/></r></p></e>
<e r="LR"><p><l>pro<b/>tio<b/>ke<s n="cnjadv"/></l><r>since<s n="cnjadv"/></r></p></e>
</pre>

If either value is zero or negative, no alignment will be done.

==Usage==
<pre>
Usage: apertium-dixtools format-1line [alignP alignR] <input-dic> <output-dic>
where alignP / alignR: column to align <p> and <r> entries. 0 = no indent.

Example: ' format-1line old.dix new.dix ' will give indent à la
<e><p><l>dum<s n="cnjadv"/></l><r>whereas<s n="cnjadv"/></r></p></e>

Example: ' format-1line 10 50 old.dix new.dix ' will give indent à la
<e> <p><l>dum<s n="cnjadv"/></l> <r>whereas<s n="cnjadv"/></r></p></e>

Example: ' format-1line 0 50 old.dix new.dix ' will give indent à la
<e><p><l>dum<s n="cnjadv"/></l> <r>whereas<s n="cnjadv"/></r></p></e>

Example: ' format-1line 10 0 old.dix new.dix ' will give indent à la
<e> <p><l>dum<s n="cnjadv"/></l><r>whereas<s n="cnjadv"/></r></p></e>
</pre>


[[Category:Tools]]
[[Category:Tools]]
[[Category:Development]]
[[Category:Dixtools]]
[[Category:Documentation in English]]

Latest revision as of 00:18, 24 March 2020

En français

You can use the Apertium-dixtools package to format each <e> tag in the dictionary.

$ apertium-dixtools format-1line <dic> <dic.out>

(Note that the first character in the 1line parameter is the digit 1 (one), not the lowercase "L".)

For example, these lines:

...
<e>
  <p>
    <l>estilo<s n="n"/></l>
    <r>estil<s n="n"/></r>
  </p>
</e>
...

will be displayed in one line, instead of being indented to various levels on six lines:

...
<e><p><l>estilo<s n="n"/></l><r>estil<s n="n"/></r></p></e>
...

This single-line format can be useful if you use grep or any similar tool to process dictionaries.

Aligned formatting[edit]

You can also add two parameters, namely the positon of the <p> element and the position of the <r> element. Here alignP = 10 and alignR = 50:

    <!-- Conjunctions - Conjunctive adverb  -->

<e>       <p><l>antaŭ<b/>ol<s n="cnjadv"/></l>    <r>before<s n="cnjadv"/></r></p></e>
<e>       <p><l>tiel<b/>ke<s n="cnjadv"/></l>     <r>so<b/>that<s n="cnjadv"/></r></p></e>
<e>       <p><l>krom<b/>se<s n="cnjadv"/></l>     <r>unless<s n="cnjadv"/></r></p></e>
<e>       <p><l>dum<s n="cnjadv"/></l>            <r>whereas<s n="cnjadv"/></r></p></e>
<e>       <p><l>ĉar<s n="cnjadv"/></l>            <r>because<s n="cnjadv"/></r></p></e>
<e r="RL"><p><l>dum<s n="cnjadv"/></l>            <r>while<s n="cnjadv"/></r></p></e>
<e>       <p><l>ĝis<s n="cnjadv"/></l>            <r>until<s n="cnjadv"/></r></p></e>
<e>       <p><l>kiam<s n="cnjadv"/></l>           <r>when<s n="cnjadv"/></r></p></e>
<e i="yes"><p><l>kiam<s n="cnjadv"/></l>          <r>as<s n="cnjadv"/></r></p></e>
<e>       <p><l>kiel<s n="cnjadv"/></l>           <r>as<s n="cnjadv"/></r></p></e>
<e r="LR"><p><l>pro<b/>tio<b/>ke<s n="cnjadv"/></l><r>since<s n="cnjadv"/></r></p></e>

If either value is zero or negative, no alignment will be done.

Usage[edit]

Usage: apertium-dixtools format-1line [alignP alignR] <input-dic> <output-dic>
       where alignP / alignR: column to align <p> and <r> entries. 0 = no indent.

Example: ' format-1line old.dix new.dix '   will give indent à la
<e><p><l>dum<s n="cnjadv"/></l><r>whereas<s n="cnjadv"/></r></p></e>

Example: ' format-1line 10 50 old.dix new.dix '   will give indent à la
<e>       <p><l>dum<s n="cnjadv"/></l>            <r>whereas<s n="cnjadv"/></r></p></e>

Example: ' format-1line 0 50 old.dix new.dix '   will give indent à la
<e><p><l>dum<s n="cnjadv"/></l>                   <r>whereas<s n="cnjadv"/></r></p></e>

Example: ' format-1line 10 0 old.dix new.dix '   will give indent à la
<e>       <p><l>dum<s n="cnjadv"/></l><r>whereas<s n="cnjadv"/></r></p></e>