Difference between revisions of "Format dictionaries"

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{{Otherlang|Formatage de dictionnaires|{{French}}}}
You can use the [[Apertium-dixtools]] package) to format each '''<code><e></code>''' tag in the dictionary.

You can use the [[Apertium-dixtools]] package to format each '''<code><e></code>''' tag in the dictionary.


$ apertium-dixtools '''format-1line''' <dic> <dic.out>
$ apertium-dixtools '''format-1line''' <dic> <dic.out>
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</pre>
</pre>


will be displayed in one line, instead of being indented to various levels on six lines.
will be displayed in one line, instead of being indented to various levels on six lines:


<pre>
<pre>
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==Usage==
==Usage==
<pre>
<pre>
Usage: dictools format-1line [alignP alignR] <input-dic> <output-dic>
Usage: apertium-dixtools format-1line [alignP alignR] <input-dic> <output-dic>
where alignP / alignR: column to align <p> and <r> entries. 0 = no indent.
where alignP / alignR: column to align <p> and <r> entries. 0 = no indent.



Latest revision as of 00:18, 24 March 2020

En français

You can use the Apertium-dixtools package to format each <e> tag in the dictionary.

$ apertium-dixtools format-1line <dic> <dic.out>

(Note that the first character in the 1line parameter is the digit 1 (one), not the lowercase "L".)

For example, these lines:

...
<e>
  <p>
    <l>estilo<s n="n"/></l>
    <r>estil<s n="n"/></r>
  </p>
</e>
...

will be displayed in one line, instead of being indented to various levels on six lines:

...
<e><p><l>estilo<s n="n"/></l><r>estil<s n="n"/></r></p></e>
...

This single-line format can be useful if you use grep or any similar tool to process dictionaries.

Aligned formatting[edit]

You can also add two parameters, namely the positon of the <p> element and the position of the <r> element. Here alignP = 10 and alignR = 50:

    <!-- Conjunctions - Conjunctive adverb  -->

<e>       <p><l>antaŭ<b/>ol<s n="cnjadv"/></l>    <r>before<s n="cnjadv"/></r></p></e>
<e>       <p><l>tiel<b/>ke<s n="cnjadv"/></l>     <r>so<b/>that<s n="cnjadv"/></r></p></e>
<e>       <p><l>krom<b/>se<s n="cnjadv"/></l>     <r>unless<s n="cnjadv"/></r></p></e>
<e>       <p><l>dum<s n="cnjadv"/></l>            <r>whereas<s n="cnjadv"/></r></p></e>
<e>       <p><l>ĉar<s n="cnjadv"/></l>            <r>because<s n="cnjadv"/></r></p></e>
<e r="RL"><p><l>dum<s n="cnjadv"/></l>            <r>while<s n="cnjadv"/></r></p></e>
<e>       <p><l>ĝis<s n="cnjadv"/></l>            <r>until<s n="cnjadv"/></r></p></e>
<e>       <p><l>kiam<s n="cnjadv"/></l>           <r>when<s n="cnjadv"/></r></p></e>
<e i="yes"><p><l>kiam<s n="cnjadv"/></l>          <r>as<s n="cnjadv"/></r></p></e>
<e>       <p><l>kiel<s n="cnjadv"/></l>           <r>as<s n="cnjadv"/></r></p></e>
<e r="LR"><p><l>pro<b/>tio<b/>ke<s n="cnjadv"/></l><r>since<s n="cnjadv"/></r></p></e>

If either value is zero or negative, no alignment will be done.

Usage[edit]

Usage: apertium-dixtools format-1line [alignP alignR] <input-dic> <output-dic>
       where alignP / alignR: column to align <p> and <r> entries. 0 = no indent.

Example: ' format-1line old.dix new.dix '   will give indent à la
<e><p><l>dum<s n="cnjadv"/></l><r>whereas<s n="cnjadv"/></r></p></e>

Example: ' format-1line 10 50 old.dix new.dix '   will give indent à la
<e>       <p><l>dum<s n="cnjadv"/></l>            <r>whereas<s n="cnjadv"/></r></p></e>

Example: ' format-1line 0 50 old.dix new.dix '   will give indent à la
<e><p><l>dum<s n="cnjadv"/></l>                   <r>whereas<s n="cnjadv"/></r></p></e>

Example: ' format-1line 10 0 old.dix new.dix '   will give indent à la
<e>       <p><l>dum<s n="cnjadv"/></l><r>whereas<s n="cnjadv"/></r></p></e>