Difference between revisions of "Inconditional section"

From Apertium
Jump to navigation Jump to search
(New page: An inconditional ('unconditional') section of a dictionary typically contains punctuation, and such things. The main section of a dictionary works on a longest-match basis. Inconditiona...)
 
Line 26: Line 26:
 
</section>
 
</section>
 
</dictionary>
 
</dictionary>
  +
jim@jim-laptop:~/Devel/apertium-git/incubator/apertium-en-it$ echo aaa |lt-proc sample.bin
 
  +
$ echo aaa |lt-proc sample.bin
 
^aa/aa<aa>$^a/a<aa>$
 
^aa/aa<aa>$^a/a<aa>$
  +
jim@jim-laptop:~/Devel/apertium-git/incubator/apertium-en-it$ echo aaaa |lt-proc sample.bin
 
  +
$ echo aaaa |lt-proc sample.bin
 
^aa/aa<aa>$^aa/aa<aa>$
 
^aa/aa<aa>$^aa/aa<aa>$
  +
jim@jim-laptop:~/Devel/apertium-git/incubator/apertium-en-it$ echo aaaaa |lt-proc sample.bin
 
  +
$ echo aaaaa |lt-proc sample.bin
 
^aa/aa<aa>$^aa/aa<aa>$^a/a<aa>$
 
^aa/aa<aa>$^aa/aa<aa>$^a/a<aa>$
 
</pre>
 
</pre>

Revision as of 19:17, 17 September 2009

An inconditional ('unconditional') section of a dictionary typically contains punctuation, and such things.

The main section of a dictionary works on a longest-match basis.

Inconditional means 'if you see this, stop processing immediately and start reading a new word'. Stop when you reach the end of a possible transduction.

You could say that the "only" difference is that a space is not required to start a new match.

$ echo 23men |apertium -d . en-it-anmor
^23/23<num>$^men/man<n><pl>$^./.<sent>$

It doesn't need the space between 23 and men because numbers are in an 'inconditional' section.

<dictionary>
  <alphabet>ab</alphabet>
  <sdefs>
    <sdef n="aa"/>
    <sdef n="ab"/>
  </sdefs>
  <section id="foo" type="inconditional">
    <e><p><l>a</l><r>a<s n="aa"/></r></p></e>
    <e><p><l>aa</l><r>aa<s n="aa"/></r></p></e>
  </section>
</dictionary>

$ echo aaa |lt-proc  sample.bin
^aa/aa<aa>$^a/a<aa>$

$ echo aaaa |lt-proc  sample.bin
^aa/aa<aa>$^aa/aa<aa>$

$ echo aaaaa |lt-proc  sample.bin
^aa/aa<aa>$^aa/aa<aa>$^a/a<aa>$